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10 cards from this deck
Summation of series, divisibility, matrix products
Base case - verify formula for n=1n=1n=1 or starting value
Assume formula holds for n=kn=kn=k
Prove formula holds for n=k+1n=k+1n=k+1
n(n+1)(2n+1)6\frac{n(n+1)(2n+1)}{6}6n(n+1)(2n+1)
f(k+1)=f(k)+(some multiple of k)f(k+1) = f(k) + \text{(some multiple of } k\text{)}f(k+1)=f(k)+(some multiple of k)
kmkmkm for some integer mmm
Failing to clearly define it
Errors simplifying expressions (powers, coefficients)
Misapplying initial conditions
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