See what we can offer to your school
"SimpleStudy just makes sense...”
Get the best plan for your school
12 questions from this quiz
sinθ\sin \thetasinθ
Direction vectors
Normal vectors
cosθ=b1⋅b2∣b1∣∣b2∣\cos \theta = \frac{\mathbf{b}_1 \cdot \mathbf{b}_2}{|\mathbf{b}_1||\mathbf{b}_2|}cosθ=∣b1∣∣b2∣b1⋅b2
Normal vector to the plane
Neglecting to normalise vectors
Cartesian form
cosθ=n1⋅n2∣n1∣∣n2∣\cos \theta = \frac{\mathbf{n}_1 \cdot \mathbf{n}_2}{|\mathbf{n}_1||\mathbf{n}_2|}cosθ=∣n1∣∣n2∣n1⋅n2
Finding angles between vectors
Using cosθ\cos \thetacosθ for line-plane angle
sinθ=b⋅n∣b∣∣n∣\sin \theta = \frac{\mathbf{b} \cdot \mathbf{n}}{|\mathbf{b}||\mathbf{n}|}sinθ=∣b∣∣n∣b⋅n
Direction vectors of the lines
Select your subjects, and get access to A+ resources today.