Moments (Edexcel A-Level Mathematics): Quizzes

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Centres of Mass
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For a uniform rod, where does its weight act?

At its centre

Distance from pivot to centre for a 1.51.5 m rod?

0.750.75 m

Which equation matches Method 1 moments?

5gsin⁡30∘×0.75−Fcos⁡30∘×1.5=05g \sin30^\circ \times 0.75 - F \cos30^\circ \times 1.5 = 0

Expression for FF from the moment eqn?

F=5gsin⁡30∘×0.75cos⁡30∘×1.5F=\frac{5g \sin 30^\circ \times 0.75}{\cos 30^\circ \times 1.5}

Numeric value of FF from the worked solution?

14.1514.15 N

Perpendicular distance of weight from pivot in Method 2?

0.75sin⁡30°0.75 \sin 30°

Perpendicular distance of FF from pivot in Method 2?

1.5cos⁡30°1.5 \cos 30°

Taking moments about the pivot removes which forces?

Hinge reaction forces

Equilibrium condition for moments used in note?

Sum of moments =0= 0

Where is the centre of mass of a uniform rod located?

Midpoint of rod

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