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12 cards from this deck
¬A∨¬B\neg A \lor \neg B¬A∨¬B
¬A∧¬B\neg A \land \neg B¬A∧¬B
Flip the operator and negate each operand
(A∨B)∧(A∨C)(A \lor B) \land (A \lor C)(A∨B)∧(A∨C)
(A∧B)∨(A∧C)(A \land B) \lor (A \land C)(A∧B)∨(A∧C)
No, grouping doesn't affect result
Order doesn't matter; A∨B=B∨AA \lor B = B \lor AA∨B=B∨A
AAA
Associative is grouping (parentheses)
Commutative is order (swapping terms)
111 (or True)
000 (or False)
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