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Monochromatic light of wavelength $5.8 imes 10^{-7} ext{ m}$ is incident normally on a plane transmission diffraction grating that has a slit separation of $2.5 imes 10^{-6} ext{ m}$ - AQA - A-Level Physics - Question 21 - 2022 - Paper 1

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Question 21

Monochromatic-light-of-wavelength-$5.8--imes-10^{-7}--ext{-m}$-is-incident-normally-on-a-plane-transmission-diffraction-grating-that-has-a-slit-separation-of-$2.5--imes-10^{-6}--ext{-m}$-AQA-A-Level Physics-Question 21-2022-Paper 1.png

Monochromatic light of wavelength $5.8 imes 10^{-7} ext{ m}$ is incident normally on a plane transmission diffraction grating that has a slit separation of $2.5 i... show full transcript

Worked Solution & Example Answer:Monochromatic light of wavelength $5.8 imes 10^{-7} ext{ m}$ is incident normally on a plane transmission diffraction grating that has a slit separation of $2.5 imes 10^{-6} ext{ m}$ - AQA - A-Level Physics - Question 21 - 2022 - Paper 1

Step 1

Calculate the Maximum Order of Diffraction

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Answer

To find the number of maxima produced by the grating, we use the formula for the diffraction condition:

dimesextsin(heta)=mimesextwavelengthd imes ext{sin}( heta) = m imes ext{wavelength}

where:

  • dd is the slit separation, which is 2.5imes106extm2.5 imes 10^{-6} ext{ m},
  • mm is the order of the maximum,
  • extwavelength ext{wavelength} is 5.8imes107extm5.8 imes 10^{-7} ext{ m}.

The maximum order mm is found when extsin(heta)=1 ext{sin}( heta) = 1, therefore:

m_{max} = rac{d}{ ext{wavelength}}

Substituting the known values:

m_{max} = rac{2.5 imes 10^{-6}}{5.8 imes 10^{-7}} \\ m_{max} \\approx 4.31

Since mm must be an integer, the maximum order of diffraction is 4.

Step 2

Determine the Number of Maxima

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Answer

The total number of maxima includes the zeroth order plus the orders on either side:

  • The orders from the principal maxima are m=0,ext±1,ext±2,ext±3,ext±4m = 0, \, ext{±1}, \, ext{±2}, \, ext{±3}, \, ext{±4}. This accounts for the zeroth order and the four positive and four negative orders.

Therefore, the number of maxima produced by the grating is:

1+4+4=91 + 4 + 4 = 9

Thus, the answer is 9.

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