Electrolysis of Aqueous Solutions (AQA GCSE Chemistry Combined Science): Flashcards

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Electrolysis of Aqueous Solutions
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Why is aqueous electrolysis more complex?

Water produces H⁺ and OH⁻ ions that react at electrodes

Ions from water dissociation during electrolysis

H⁺ (hydrogen ions) and OH⁻ (hydroxide ions)

Water dissociation equation

\ceH2O(l)<=>H+(aq)+OH(aq)\ce{H2O(l) <=> H+(aq) + OH-(aq)}

Ion reduced at cathode (aqueous electrolysis rule)

The less reactive ion

Ion oxidised at anode (aqueous electrolysis rule)

The ion that can be oxidised more easily

Ion reduced at cathode in CuSO₄ solution

Cu²⁺ (copper is less reactive than hydrogen)

Product at cathode in CuSO₄ electrolysis

Solid copper deposits on cathode

Cathode half-equation in CuSO₄ electrolysis

\ceCu2+(aq)+2e>Cu(s)\ce{Cu^{2+}(aq) + 2e- -> Cu(s)}

Ion oxidised at anode when no halides present

OH⁻ ions (from water)

Anode half-equation for OH⁻ oxidation

\ce4OH(aq)>2H2O(l)+O2(g)+4e\ce{4OH-(aq) -> 2H2O(l) + O2(g) + 4e-}

Products from OH⁻ oxidation at anode

Oxygen gas (O₂) and water

Reactive cations (Na⁺) behaviour at cathode

They remain; H⁺ ions reduced instead

Ion oxidised at anode if halide ions present

Halide ions (e.g. Cl⁻)

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