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Where cumulative frequency just exceeds n/2
Frequency divided by class width
Median position may be a decimal, expected in answer
Estimated median = 8.5
n = 190
Estimated median = 42.5 years
Estimated median = 5 + 3.5 = 8.5
95; in 35<y≤45 (3rd class)
Median = 35 + (95-65)/4 = 42.5
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