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10 questions from this quiz
Type 2 reactions
Occurs without ongoing energy input
Types 1 and 2 only
100.0 kPa
Spontaneous to completion
ΔG∘=ΔH∘−TΔS∘\Delta G^\circ = \Delta H^\circ - T\Delta S^\circΔG∘=ΔH∘−TΔS∘
Multiply by 10−310^{-3}10−3 to get kJ K−1^{-1}−1 mol−1^{-1}−1
High T makes ΔG∘\Delta G^\circΔG∘ more negative
Require continuous heating
±40\pm 40±40 kJ mol−1^{-1}−1
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