Finding Ka (AQA A-Level Chemistry): Flashcards

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Finding Ka
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Relationship between pH and pKapK_a at half-equivalence point

pH=pKapH = pK_a

Relationship between [HA] and [A⁻] at half-equivalence

[HA]=[A−][HA] = [A^-]

Formula for KaK_a from pH

Ka=[H+]=10−extpHK_a = [H^+] = 10^{- ext{pH}}

Volume of ethanoic acid used in titration

25.0 cm³

Phenolphthalein colour change at equivalence point

Colourless to pink

How to find half-equivalence point volume

Use half the volume of NaOH used to reach equivalence

pH values for calibrating pH meter

pH 4.00, 7.00, and 10.00

Specimen pH at half-equivalence point

4.75

Calculated KaK_a from pH 4.75

1.8×10−51.8 \times 10^{-5} mol dm⁻³

Typical KaK_a range for weak acids like ethanoic acid

Around 10−510^{-5} mol dm⁻³

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