Resolving Forces & Inclined Planes (AQA A-Level Mathematics): Flashcards

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Resolving Forces & Inclined Planes
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Assumption when no friction mentioned on slope

Assume slope is smooth

Weight component parallel to slope

mgsinθmg \sin \theta

Weight component perpendicular to slope

mgcosθmg \cos \theta

What is equilibrium?

When forces completely cancel each other out

Direction of normal reaction force RR on slope

Perpendicular to the slope

Two directions for resolving forces on slope

Parallel and perpendicular to slope

Direction friction acts on inclined plane

Parallel to plane, opposes motion

Formula for friction force

Ffriction=μFnormalF_{\text{friction}} = \mu F_{\text{normal}}

Smooth pulley assumption implies

Tension is same on both sides of pulley

Normal force on slope equals

mgcos(θ)mg \cos(\theta)

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