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10 cards from this deck
The boundary associated with a given probability
Area to the LEFT of a boundary
Calculate area to the left: 1−P(X>b)1 - P(X > b)1−P(X>b)
Number of standard deviations from the mean
z=X−μσz = \frac{X - \mu}{\sigma}z=σX−μ
Yes, because normal distribution is symmetrical about the mean
Calculate z algebraically, find z from N(0,1)N(0,1)N(0,1) using inverse normal, solve equations simultaneously
P(X<c)=P(X<a)+P(a<X<c)P(X < c) = P(X < a) + P(a < X < c)P(X<c)=P(X<a)+P(a<X<c)
z standardizes values by measuring standard deviations from the mean
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