See what we can offer to your school
"SimpleStudy just makes sense...”
Get the best plan for your school
10 questions from this quiz
f(x)f(x)f(x) is concave up on that interval
The first derivative is decreasing
Solve f′′(x)=0f''(x) = 0f′′(x)=0 or where f′′(x)f''(x)f′′(x) is undefined
f′(c)=0f'(c) = 0f′(c)=0 and f′′(c)>0f''(c) > 0f′′(c)>0
f′′(c)<0f''(c) < 0f′′(c)<0
666
When f′(x)=0f'(x) = 0f′(x)=0 and f′′(x)=0f''(x) = 0f′′(x)=0
P′′(x)<0P''(x) < 0P′′(x)<0 (concave down)
Acceleration a(t)a(t)a(t)
f′′(x)≥0f''(x) \geq 0f′′(x)≥0
Select your subjects, and get access to A+ resources today.