Implicit Differentiation (AQA A-Level Mathematics): Flashcards

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Implicit Differentiation
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What is implicit differentiation?

Finding derivative when yy not explicitly solved for in terms of xx

When to use implicit differentiation

Implicit equations, relations, circles (where yy not isolated)

ddx\frac{d}{dx} equivalent to

ddy×dydx\frac{d}{dy} \times \frac{dy}{dx}

ddx(y2)\frac{d}{dx}(y^2) equals

2ydydx2y \frac{dy}{dx}

Steps for implicit differentiation

  1. Diff both sides w.r.t. xx, 2. Collect dydx\frac{dy}{dx} terms, 3. Solve for dydx\frac{dy}{dx}

Rule applied when differentiating yy terms

Chain rule (introduces dydx\frac{dy}{dx})

dydx\frac{dy}{dx} for x2+y2=1x^2 + y^2 = 1

xy\frac{-x}{y}

Applications of implicit differentiation

Tangent/normal lines, related rates, inverse function derivatives

ddx(xy)\frac{d}{dx}(xy) using product rule

y+xdydxy + x\frac{dy}{dx}

Finding stationary points implicitly

Set dydx=0\frac{dy}{dx} = 0 and solve

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