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10 questions from this quiz
When yyy is not isolated (e.g. x2+y2=1x^2+y^2=1x2+y2=1)
ddy×dydx\frac{d}{dy} \times \frac{dy}{dx}dyd×dxdy
2ydydx2y \frac{dy}{dx}2ydxdy
−xy\frac{-x}{y}y−x
y+xdydxy + x\frac{dy}{dx}y+xdxdy
It leverages the chain rule
x2+y2+5xy=cosxx^2 + y^2 + 5xy = \cos xx2+y2+5xy=cosx
Set it equal to 0
Finding tangent line slopes
Yes, differentiate dydx\frac{dy}{dx}dxdy again
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