Comparing gravitational fields and electrical fields (AQA A-Level Physics): Flashcards

$F = \frac{Gm_1m_2}{r^2}$

$F = \frac{Q_1Q_2}{4\pi\varepsilon_0 r^2}$

Always attractive

Attractive (opposite charges) or repulsive (like charges)

Force per unit mass

Force per unit charge

$V = -\frac{GM}{r}$

$V = \frac{Q}{4\pi\varepsilon_0 r}$

$g = -\frac{\Delta V}{\Delta r}$ or $E = -\frac{\Delta V}{\Delta r}$

Grav: independent; Electric: affected by permittivity