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mAuA+mBuB=mAvA+mBvBm_A u_A + m_B u_B = m_A v_A + m_B v_BmAuA+mBuB=mAvA+mBvB
e=speed of separationspeed of approache = \frac{\text{speed of separation}}{\text{speed of approach}}e=speed of approachspeed of separation
e=vB−vAuA−uBe = \frac{v_B - v_A}{u_A - u_B}e=uA−uBvB−vA
e=vreboundvimpacte = \frac{v_{\text{rebound}}}{v_{\text{impact}}}e=vimpactvrebound
vB>vAv_B > v_AvB>vA
Spheres will not collide again
v=2ghv = \sqrt{2gh}v=2gh
h=v22gh = \frac{v^2}{2g}h=2gv2
No, kinetic energy is not conserved
Final velocities of previous collision
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