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10 questions from this quiz
W=FdcosθW = Fd\cos\thetaW=Fdcosθ
W=0W = 0W=0
Change in kinetic energy
KE=12mv2KE = \frac{1}{2}mv^2KE=21mv2
606060 J
mgsinθmg\sin\thetamgsinθ
5.665.665.66 m/s
Via cosine of the angle
Net work by all forces
Joules (J)
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