Variable Acceleration - 2D (Edexcel A-Level Mathematics): Flashcards

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Using Calculus in 2D
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Method when acceleration is non-constant

Use calculus (cannot use SUVAT)

Relationship: velocity in terms of position s\mathbf{s}

v=dsdt\mathbf{v} = \frac{d\mathbf{s}}{dt}

Relationship: acceleration in terms of velocity

a=dvdt\mathbf{a} = \frac{d\mathbf{v}}{dt}

Relationship: position in terms of velocity

s=vdt\mathbf{s} = \int \mathbf{v} \, dt

Relationship: velocity in terms of acceleration

v=adt\mathbf{v} = \int \mathbf{a} \, dt

Formula for force in terms of mass and acceleration

F=ma\mathbf{F} = m\mathbf{a}

Convert mass from grams to kg

Multiply by 10310^{-3}

Distance from origin O given position (x,y)(x, y)

s=x2+y2|\mathbf{s}| = \sqrt{x^2 + y^2}

Condition for motion parallel to i\mathbf{i} vector

jj-component of velocity = 0

How to find constant of integration C\mathbf{C}

Use given boundary/initial conditions

To find velocity from position vector

Differentiate position w.r.t. time

To find acceleration from velocity

Differentiate velocity w.r.t. time

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