Constant Acceleration - 2D (Edexcel A-Level Mathematics): Quizzes

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suvat in 2D
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Why can't we use v2=u2+2asv^2 = u^2 + 2as in 2D vector form?

Squared vectors don't exist

Which 1D equation has NO valid 2D vector equivalent?

v2=u2+2asv^2 = u^2 + 2as

If a particle moves with constant velocity, what is its acceleration?

(0,0)(0, 0)

What does 'due east' mean for a position vector?

y=0y = 0, xx has a value

A particle at (2,5)(2, 5) m moves with velocity (3,2)(3, -2) m/s for 3s. Final position?

(11,1)(11, -1) m

If velocity is (3,10)(3, 10) m/s, what is the speed?

109\sqrt{109} m/s

What condition means a particle is 'north-east' of the origin?

x=yx = y

When do two particles meet?

Position vectors equal at same time

u=(2.4,0.6)\mathbf{u} = (2.4, -0.6) m/s, v=(5.6,3.4)\mathbf{v} = (-5.6, 3.4) m/s at t=20t=20 s. Find a\mathbf{a}.

(0.4,0.2)(-0.4, 0.2) m/s²

Which 2D equation finds position from initial velocity and acceleration?

s=ut+12at2\mathbf{s} = \mathbf{u}t + \frac{1}{2}\mathbf{a}t^2

Velocity (3,10)(3, 10) gives tanθ=103\tan \theta = \frac{10}{3}. How to find bearing from north?

90°θ90° - \theta

Why must we add initial position when calculating final position?

Not starting at origin (0,0)(0, 0)

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