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12 cards from this deck
There is no such thing as 'squared' vectors
v=u+at\mathbf{v} = \mathbf{u} + \mathbf{a}tv=u+at
s=ut+12at2\mathbf{s} = \mathbf{u}t + \frac{1}{2}\mathbf{a}t^2s=ut+21at2
s=12(u+v)t\mathbf{s} = \frac{1}{2}(\mathbf{u}+\mathbf{v})ts=21(u+v)t
s=vt−12at2\mathbf{s} = \mathbf{v}t - \frac{1}{2}\mathbf{a}t^2s=vt−21at2
v2=u2+2asv^2 = u^2 + 2asv2=u2+2as (contains squared vectors)
y=0y = 0y=0 and xxx has a value
xxx-coordinate equals yyy-coordinate
∣v∣=x2+y2|\mathbf{v}| = \sqrt{x^2 + y^2}∣v∣=x2+y2
Position = Initial position + Displacement
Position vectors equal at the same time
a=(0,0)\mathbf{a} = (0, 0)a=(0,0) or zero vector
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