Estimating (AQA GCSE Maths): Revision Notes
Estimating
What is estimating?
Estimating in mathematics doesn't mean making a wild guess. Instead, it's a systematic approach where you look at the numbers in a problem, simplify them to make calculations easier, and then work through the problem. While your final answer won't be as precise as the exact calculation, it will be much easier to work with and still give you a reasonable result.
The key to successful estimating is using your rounding skills effectively. This makes complex calculations manageable while still providing useful answers.
The difference between estimating and guessing is crucial: estimating involves a deliberate method of simplifying numbers, while guessing has no systematic approach behind it.
Estimating calculations
When you need to estimate the result of complex calculations, there's a straightforward method you can follow. The main strategy involves rounding numbers to make them easier to work with, typically to 1 or 2 significant figures.
Basic method for estimating calculations:
- Identify all the numbers in your calculation
- Round them to simpler values (usually 1 or 2 significant figures)
- If the calculation is still complex, round again to make it even easier
- Perform the calculation with your simplified numbers
Worked example: Complex fraction
Worked Example: Estimating a Complex Fraction
Estimate the value of
Step 1: Round all numbers to easier values
- 127.8 becomes 130
- 41.9 becomes 40
- 56.5 becomes 60
- 3.2 becomes 3
Step 2: Substitute the rounded values
Step 3: Simplify further if needed Round 170 to 180, giving you
Answer: The estimate is 1
Worked example: Volume calculation
Worked Example: Volume of a Cylinder
A cylindrical glass has a height of 18 cm and radius of 3 cm. Estimate its volume using .
Step 1: Round values to 1 significant figure
- height = 18 cm 20 cm
- radius = 3 cm (already simple)
Step 2: Substitute into the formula
Step 3: Apply to practical problem If filling glasses from a 2.5 litre bottle:
- Convert: 2.5 litres = 2500 cm³
- Round 540 to 500 for easier division
- Number of glasses: glasses
Answer: The glass volume is approximately 540 cm³
Estimating square roots
Estimating square roots follows a specific two-step process that makes use of perfect squares you already know.
The Two-Step Method for Square Roots:
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Find boundary square numbers: Identify two perfect squares that your given number falls between - one smaller and one larger than your number.
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Determine closeness: Decide which perfect square your number is closer to, then make a reasonable estimate for the digit after the decimal point.
Worked example: Estimating √87
Worked Example: Estimating
Estimate to 1 decimal place.
Step 1: Find the perfect squares on either side of 87
So 87 falls between 81 and 100, meaning is between 9 and 10.
Step 2: Determine which it's closer to Since 87 is closer to 81 than to 100, will be closer to 9 than to 10.
Step 3: Make a sensible estimate
Verification: The actual value of is approximately 9.32737, so our estimate is very reasonable.
Exam technique
When answering estimation questions in your exam, always show your working clearly. This means writing down what you've rounded each number to, as this proves you haven't simply used a calculator to find the exact answer. Demonstrating your method step-by-step is essential for earning full marks.
Critical Exam Advice:
Remember that estimation questions often ask you to show "all your working" - this is your cue to be thorough in showing your rounding steps and subsequent calculations. Without showing your method, you may lose marks even if your final answer is correct.
Remember!
Key Points to Remember:
- Estimating means making numbers easier to work with, not guessing randomly
- Round numbers to 1 or 2 significant figures to simplify calculations
- For square roots, find perfect squares on either side of your number, then decide which is closer
- Always show your rounding steps clearly in exam answers
- You can round multiple times if it makes calculations easier
- The goal is to make calculations manageable while maintaining reasonable accuracy