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11 cards from this deck
Stopping distance increases
Thinking distance increases proportionally; braking distance increases at a higher rate
Increases at same rate as speed (proportionally)
Reaction time constant, but more distance covered at higher speed
Braking distance increases
More speed = more KE, so more work needed to stop
KE=12mv2KE = \frac{1}{2}mv^2KE=21mv2
KE increases at higher rate than speed (speed is squared)
More work needed to transfer greater KE (constant braking force)
W=FsW = FsW=Fs
Compare stopping distances of different vehicles at specific speeds
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