Percentage composition example (Edexcel GCSE Chemistry): Flashcards

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Percentage composition example
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Formula for % mass of element in compound

Ar×atoms×100RFM\frac{\text{Ar} \times \text{atoms} \times 100}{\text{RFM}}

Relative atomic mass (Ar) of Na

23

Relative atomic mass (Ar) of S

32

Relative atomic mass (Ar) of O

16

RFM of Na2SO4Na_2SO_4

142

Calculation for RFM of Na2SO4Na_2SO_4

(23×2)+32+(16×4)=142(23 \times 2) + 32 + (16 \times 4) = 142

Mass of Na in Na2SO4Na_2SO_4

23×2=4623 \times 2 = 46

% mass of Na in Na2SO4Na_2SO_4

46142×100=32.4%\frac{46}{142} \times 100 = 32.4\%

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