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12 cards from this deck
Stopping distance increases
At the same rate
Constant reaction time but more distance covered at higher speed
More kinetic energy at higher speeds (increases at a higher rate)
KE=12mv2KE = \frac{1}{2}mv^2KE=21mv2
At a higher rate
More work needed to transfer more KE (constant braking force)
W=FsW = FsW=Fs
23m
29m
Blue vehicle
Reaction time
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