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10 cards from this deck
Stopping distance generally increases
At same rate as speed
Reaction time constant, but speed changes
Braking distance increases
More KE due to v2v^2v2 relationship; increases at higher rate than speed
KE=12mv2KE = \frac{1}{2}mv^2KE=21mv2
More work needed to transfer KE (constant braking force)
W=FsW = FsW=Fs
Compare different vehicles' stopping distances
Blue: 23m, Red: 29m (Blue shorter)
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