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12 cards from this deck
Events where one outcome doesn't affect another
Multiply probabilities when both independent events must happen
Add probabilities when either event can happen
Putting item back so total & probabilities stay same
12×12=14\frac{1}{2} \times \frac{1}{2} = \frac{1}{4}21×21=41
1−P(both tails)=1−14=341 - P(\text{both tails}) = 1 - \frac{1}{4} = \frac{3}{4}1−P(both tails)=1−41=43
16×16=136\frac{1}{6} \times \frac{1}{6} = \frac{1}{36}61×61=361
4 aces
452=113\frac{4}{52} = \frac{1}{13}524=131
26 cards (hearts & diamonds)
2,4,62, 4, 62,4,6 so P(even) = 36=12\frac{3}{6} = \frac{1}{2}63=21
Subtract probability from 1
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