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10 cards from this deck
y=ax+qy = \frac{a}{x} + qy=xa+q where a≠0a \neq 0a=0
{x:x∈R,x≠0}\{x : x \in \mathbb{R}, x \neq 0\}{x:x∈R,x=0}
{y:y∈R,y≠q}\{y : y \in \mathbb{R}, y \neq q\}{y:y∈R,y=q}
x=0x = 0x=0
y=qy = qy=q
No, it is undefined at x=0x = 0x=0
x=−aqx = -\frac{a}{q}x=−qa
Vertical shift (up if q>0q > 0q>0, down if q<0q < 0q<0)
First and third quadrants
Second and fourth quadrants
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