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10 cards from this deck
Divide displacement by time
Vector quantity
v⃗=v⃗x+v⃗y\vec{v} = \vec{v}_x + \vec{v}_yv=vx+vy
v=vx2+vy2v = \sqrt{v_x^2 + v_y^2}v=vx2+vy2
vx=vcosθv_x = v\cos\thetavx=vcosθ
vy=vsinθv_y = v\sin\thetavy=vsinθ
tanθ=vyvx\tan\theta = \frac{v_y}{v_x}tanθ=vxvy
Δv⃗=v⃗f−v⃗i\Delta\vec{v} = \vec{v}_f - \vec{v}_iΔv=vf−vi
a⃗=Δv⃗t\vec{a} = \frac{\Delta\vec{v}}{t}a=tΔv
No, they have different units
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