Charged Particles in Uniform Electric Fields (HSC SSCE Physics): Quizzes

$E = \frac{F}{q}$

Approximately $100\text{ V} \cdot \text{m}^{-1}$

Field strength; closer lines mean stronger

$E = -\frac{\Delta V}{d}$

$8000\text{ V} \cdot \text{m}^{-1}$

$a = \frac{Eq}{m}$

Opposite to the field direction

$W = -q\Delta V$

$\Delta U + \Delta K = 0$

Toward lower potential