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10 questions from this quiz
The viewpoint from which motion is observed
v⃗1 relative to 2=v⃗1−v⃗2\vec{v}_{1 \text{ relative to } 2} = \vec{v}_1 - \vec{v}_2v1 relative to 2=v1−v2
Add the negative of the second vector
Moving backwards at 2 m/s
Pythagoras' theorem
To counteract the river's current
When velocities are not perpendicular
25 m/s
s⃗1 relative to 2=d⃗1−d⃗2\vec{s}_{1 \text{ relative to } 2} = \vec{d}_1 - \vec{d}_2s1 relative to 2=d1−d2
tanθ\tan \thetatanθ
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