Calculating Concentration (VCE SSCE Chemistry): Flashcards

Relationship between solute and solvent amounts

High ratio of solute to solvent

$c = \frac{m}{V}$ (m in g, V in L)

$\frac{\text{mass (mg)}}{\text{mass soln (kg)}}$

Symbol M, unit mol/L (moles per litre)

$c = \frac{n}{V}$ (n in mol, V in L)

$n = c \times V$

$c_1V_1 = c_2V_2$

Amount of solute (number of particles)

Add acid to water, never water to acid