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10 questions from this quiz
ΔG=ΔH−TΔS\Delta G = \Delta H - T\Delta SΔG=ΔH−TΔS
Zero or negative
Spontaneous
ΔH<0\Delta H < 0ΔH<0 (releases energy)
ΔS>0\Delta S > 0ΔS>0 (increases disorder)
Divide by 1000 to get kJ
+20+20+20 kJ mol−1^{-1}−1
ΔS=ΔHT\Delta S = \frac{\Delta H}{T}ΔS=TΔH
T=ΔHΔST = \frac{\Delta H}{\Delta S}T=ΔSΔH
Reaction may become feasible as T increases
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