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10 questions from this quiz
ΔG=ΔH−TΔS\Delta G = \Delta H - T \Delta SΔG=ΔH−TΔS
When ΔG\Delta GΔG is zero or negative
Feasible at all temperatures
ΔH\Delta HΔH positive, ΔS\Delta SΔS negative
ΔH\Delta HΔH negative, ΔS\Delta SΔS negative
ΔH\Delta HΔH positive, ΔS\Delta SΔS positive
Enthalpy change and entropy change
The reaction is feasible at all temperatures
Conditions under which reaction proceeds
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