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10 questions from this quiz
Logarithmic
Tenfold change
pH=−log10[H+]\text{pH} = -\log_{10} [\text{H}^+]pH=−log10[H+]
[H+]=10−pH[\text{H}^+] = 10^{-\text{pH}}[H+]=10−pH
7.00
pH < 7.00
They fully dissociate
Two
-0.30
0.05 mol dm−3^{-3}−3
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