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10 questions from this quiz
Simplest whole-number ratio of atoms
CH2OCH_2OCH2O
Actual number of atoms of each element
Whole-number multiple of empirical
n=Mr(Molecular)Mr(Empirical)n = \frac{M_r(\text{Molecular})}{M_r(\text{Empirical})}n=Mr(Empirical)Mr(Molecular)
Convert masses to moles using MassAr\frac{\text{Mass}}{A_r}ArMass
CH2CH_2CH2
C6H12O6C_6H_{12}O_6C6H12O6
Multiply all values by 2
1:2:1
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