Variable Acceleration - 2D (AQA A-Level Mathematics): Flashcards

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Using Calculus in 2D
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When SUVAT equations cannot be used

When acceleration is non-constant; use calculus instead

Relationship: dsdt\frac{d\mathbf{s}}{dt}

v\mathbf{v} (velocity)

Relationship: dvdt\frac{d\mathbf{v}}{dt}

a\mathbf{a} (acceleration)

Integral to find displacement from velocity

s=vdt\mathbf{s} = \int \mathbf{v} \, dt

Integral to find velocity from acceleration

v=adt\mathbf{v} = \int \mathbf{a} \, dt

How to find velocity from position vector r\mathbf{r}

Differentiate r\mathbf{r} with respect to tt

How to find acceleration from velocity v\mathbf{v}

Differentiate v\mathbf{v} with respect to tt

Force equation with mass mm and acceleration a\mathbf{a}

F=ma\mathbf{F} = m\mathbf{a}

Converting mass: 3 grams to kg

3×1033 \times 10^{-3} kg or 0.003 kg

Condition for particle moving parallel to i\mathbf{i}

jj-component of velocity =0= 0

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