Constant Acceleration - 2D (AQA A-Level Mathematics): Flashcards

Vectors cannot be squared

$\mathbf{v} = \mathbf{u} + \mathbf{a}t$

$\mathbf{s} = \mathbf{u}t + \frac{1}{2}\mathbf{a}t^2$

$\mathbf{s} = \mathbf{v}t - \frac{1}{2}\mathbf{a}t^2$

$y = 0$ and $x$ has a value

$x = y$ (x-coordinate equals y-coordinate)

$\mathbf{a} = (0, 0)$ or $\mathbf{a} = \mathbf{0}$

$|\mathbf{v}| = \sqrt{v_x^2 + v_y^2}$

Position vectors equal at same time

$v^2 = u^2 + 2as$