Centres of Mass (AQA A-Level Mathematics): Flashcards

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Centres of Mass
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Model assumption for lever

Uniform rod

Where weight of rod acts

At centre of mass

Equilibrium condition for horizontal forces

Fx=0\sum F_x = 0

Equilibrium condition for vertical forces

Fy=0\sum F_y = 0

Friction force formula

F=μNF = \mu N

Method 1 for 2D moments

Resolve forces into perpendicular/parallel components

Method 2 for 2D moments

Resolve perpendicular distances to forces

Best pivot point for moments

Where unknown forces pass through

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