Further Solving Quadratic Equations (Hidden Quadratics) (AQA A-Level Mathematics): Flashcards

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Further Solving Quadratic Equations (Hidden Quadratics)
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What are hidden/stealth quadratics?

Equations with a quadratic hidden inside them

Technique to solve hidden quadratics

Substitution with simpler variable like uu

Substitution for x4x^4 terms

u=x2u = x^2, so u2=x4u^2 = x^4

Substitution for x\sqrt{x} terms

u=xu = \sqrt{x}, so u2=xu^2 = x

3 steps to solve hidden quadratics

Substitute, Solve for uu, Substitute back

Solve: x46x2+9=0x^4 - 6x^2 + 9 = 0

x=±3x = \pm\sqrt{3}

Solve: x+8x20=0x + 8\sqrt{x} - 20 = 0

x=4x = 4

Why reject u=10u = -10 when u=xu = \sqrt{x}?

Square roots must be non-negative (0\geq 0)

Does x4+8x2+12=0x^4 + 8x^2 + 12 = 0 have real roots?

No real roots

Why can't u=2u = -2 if u=x2u = x^2?

Square numbers cannot be negative

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