Further Solving Quadratic Equations (Hidden Quadratics) (AQA A-Level Mathematics): Quizzes

📚Quizzes
Further Solving Quadratic Equations (Hidden Quadratics)
Sign up to keep practising.Create a free account to play more quizzes and track your progress.

Practise the questions

10 questions from this quiz

Show

What is a 'hidden quadratic'?

An equation with a quadratic hidden inside

For x45x2+6=0x^4 - 5x^2 + 6 = 0, what substitution should be used?

u=x2u = x^2

For x+8x20=0x + 8\sqrt{x} - 20 = 0, what substitution should be used?

u=xu = \sqrt{x}

What are the solutions to x46x2+9=0x^4 - 6x^2 + 9 = 0?

x=±3x = \pm\sqrt{3}

After substituting u=x2u = x^2 in x46x2+9=0x^4 - 6x^2 + 9 = 0, what equation results?

u26u+9=0u^2 - 6u + 9 = 0

In x+8x20=0x + 8\sqrt{x} - 20 = 0, why is u=10u = -10 not valid?

Square roots must be non-negative

What is the solution to x+8x20=0x + 8\sqrt{x} - 20 = 0?

x=4x = 4

How many real roots does x4+8x2+12=0x^4 + 8x^2 + 12 = 0 have?

No real roots

Why does x4+8x2+12=0x^4 + 8x^2 + 12 = 0 have no real roots?

A square number cannot be negative

Why use substitution to solve hidden quadratics?

To simplify the equation to standard form

Join 100,000+ A-Level students studying Quizzes with us.

Select your subjects, and get access to A+ resources today.