Chain Rule (AQA A-Level Mathematics): Flashcards

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Chain Rule
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Purpose of the chain rule

Differentiate composite functions (function within function)

Chain rule formula for y=f(g(x))y = f(g(x))

dydx=f(g(x))g(x)\frac{dy}{dx} = f'(g(x)) \cdot g'(x)

Chain rule in Leibniz notation

dydx=dydududx\frac{dy}{dx} = \frac{dy}{du} \cdot \frac{du}{dx}

ddx(ex)=?\frac{d}{dx}(e^x) = ?

exe^x

ddx(ln(x))=?\frac{d}{dx}(\ln(x)) = ?

1x\frac{1}{x}

ddx(sin(3x))=?\frac{d}{dx}(\sin(3x)) = ?

3cos(3x)3\cos(3x)

When to use chain rule

Function wrapped within another function (not just multiplication)

Chain rule for y=f(g(h(x)))y = f(g(h(x)))

f(g(h(x)))g(h(x))h(x)f'(g(h(x))) \cdot g'(h(x)) \cdot h'(x)

Shortcut chain rule method

Differentiate outer, multiply by inner derivative

ddx(ex2+2)=?\frac{d}{dx}(e^{x^2+2}) = ?

2xex2+22xe^{x^2+2}

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