Product Rule (AQA A-Level Mathematics): Flashcards

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Product Rule
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Product rule formula: ddx[u⋅v]=?\frac{d}{dx}[u \cdot v] = ?

u⋅v′+v⋅u′u \cdot v' + v \cdot u'

Product rule short notation: (uv)′=?(uv)' = ?

vu′+uv′vu' + uv'

Product rule accounts for changes in...

uu changing while vv stays constant, and vv changing while uu stays constant

ddx[x2sin⁡(x)]=?\frac{d}{dx}[x^2 \sin(x)] = ?

x2cos⁡(x)+2xsin⁡(x)x^2 \cos(x) + 2x \sin(x)

ddx[exln⁡(x)]=?\frac{d}{dx}[e^x \ln(x)] = ?

exx+exln⁡(x)\frac{e^x}{x} + e^x \ln(x)

ddx[(3x2+2x)cos⁡(x)]=?\frac{d}{dx}[(3x^2 + 2x) \cos(x)] = ?

−(3x2+2x)sin⁡(x)+(6x+2)cos⁡(x)-(3x^2 + 2x)\sin(x) + (6x + 2)\cos(x)

ddx[x2e3x]=?\frac{d}{dx}[x^2 e^{3x}] = ? (factored)

e3x(3x2+2x)e^{3x}(3x^2 + 2x)

ddx[xsin⁡x]=?\frac{d}{dx}[x \sin x] = ?

sin⁡x+xcos⁡x\sin x + x \cos x

ddx[3x4e2x+3]=?\frac{d}{dx}[3x^4 e^{2x+3}] = ? (factored)

6x3e2x+3(2+x)6x^3 e^{2x+3}(2 + x)

ddx[x23x+1]=?\frac{d}{dx}[x^2 \sqrt{3x+1}] = ? (simplified)

12x(3x+1)−12(15x+4)\frac{1}{2}x(3x+1)^{-\frac{1}{2}}(15x+4)

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