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10 questions from this quiz
y=5e2xy = 5e^{2x}y=5e2x
As xxx increases, yyy decreases
Initial value at t=0t = 0t=0
k>0k > 0k>0
Population growth
Radioactive decay
ln(2)k\frac{\ln(2)}{k}kln(2)
yyy is multiplied by 2
yyy is divided by 6
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