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10 questions from this quiz
∣a∣=a12+a22|\mathbf{a}| = \sqrt{a_1^2 + a_2^2}∣a∣=a12+a22
a12+a22+a32\sqrt{a_1^2 + a_2^2 + a_3^2}a12+a22+a32
13\sqrt{13}13
252\sqrt{5}25
θ=tan−1(a2a1)\theta = \tan^{-1}\left(\frac{a_2}{a_1}\right)θ=tan−1(a1a2)
33.7°33.7°33.7°
207°207°207°
How long the vector is
−32-\frac{3}{2}−23
332\frac{3\sqrt{3}}{2}233
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