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Photoelectrons emitted from metal when light above threshold frequency
Min. frequency needed to emit photoelectrons; varies by metal
E=hfE = hfE=hf
6.63×10−346.63 \times 10^{-34}6.63×10−34 J s
One photon at a time
Min. energy to remove electron from metal surface
Voltage needed to stop photoelectrons with max. KE
Ek(max)=eVsE_{k(\text{max})} = eV_sEk(max)=eVs
hf=ϕ+Ek(max)hf = \phi + E_{k(\text{max})}hf=ϕ+Ek(max)
More photoelectrons emitted; max KE unchanged
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