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Acceleration experienced by an object in free fall under gravity only
Approximately 9.819.819.81 m/s²
Yes, regardless of mass
Always downward, towards Earth's centre
a=−9.8a = -9.8a=−9.8 m/s²
u=0u = 0u=0
v=0v = 0v=0
Still −9.8-9.8−9.8 m/s² (gravity continues acting)
Time of flight = 2×2 \times2× time to max height
Ignored unless specifically mentioned
v=u+atv = u + atv=u+at
v2=u2+2asv^2 = u^2 + 2asv2=u2+2as
s=ut+12at2s = ut + \frac{1}{2}at^2s=ut+21at2
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