Further Solving Quadratic Equations (Hidden Quadratics) (Edexcel A-Level Mathematics): Flashcards

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Further Solving Quadratic Equations (Hidden Quadratics)
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Hidden/stealth quadratics

Equations with a quadratic hidden inside them

Technique for hidden quadratics

Substitute complex terms with simpler variable (e.g., uu)

Substitution for x4x^4 in hidden quadratics

Let u=x2u = x^2, so u2=x4u^2 = x^4

Substitution for sqrtxsqrt{x} in equations

Let u=sqrtxu = sqrt{x}, so u2=xu^2 = x

Why is u=10u = -10 invalid if u=sqrtxu = sqrt{x}?

Square roots must be positive

Solve x46x2+9=0x^4 - 6x^2 + 9 = 0

x=pmsqrt3x = pmsqrt{3}

Solve x+8sqrtx20=0x + 8sqrt{x} - 20 = 0

x=4x = 4

Can x2x^2 equal a negative number (real roots)?

No, square numbers cannot be negative

Why no real roots for x4+8x2+12=0x^4 + 8x^2 + 12 = 0?

After substitution, uu values are negative (no real xx)

After solving for uu in substitution method

Substitute back to find original variable

First step solving x45x2+6=0x^4 - 5x^2 + 6 = 0

Substitute u=x2u = x^2 to get u25u+6=0u^2 - 5u + 6 = 0

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