Further Solving Quadratic Equations (Hidden Quadratics) (Edexcel A-Level Mathematics): Quizzes

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Further Solving Quadratic Equations (Hidden Quadratics)
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What is the main purpose of using substitution in hidden quadratics?

To break complex equations into simpler pieces

For an equation with x4x^4 terms, what substitution should be used?

u=x2u = x^2

For the equation x+8sqrtx20=0x + 8sqrt{x} - 20 = 0, what substitution is appropriate?

u=sqrtxu = sqrt{x}

After factorising u26u+9=0u^2 - 6u + 9 = 0, what is the value of uu?

u=3u = 3

What are the solutions to x46x2+9=0x^4 - 6x^2 + 9 = 0?

x=pmsqrt3x = pmsqrt{3}

Which factorisation is correct for u2+8u20=0u^2 + 8u - 20 = 0?

(u+10)(u2)=0(u + 10)(u - 2) = 0

Why is u=10u = -10 not valid when solving x+8sqrtx20=0x + 8sqrt{x} - 20 = 0?

Square roots must be positive

What is the solution to x+8sqrtx20=0x + 8sqrt{x} - 20 = 0?

x=4x = 4

Why does x4+8x2+12=0x^4 + 8x^2 + 12 = 0 have no real roots?

Both values of uu are negative

If x2=5x^2 = -5, what can be concluded?

There are no real roots

What is the first step when solving a hidden quadratic?

Substitute a simpler variable for complex term

After solving for uu in a hidden quadratic, what must you do?

Substitute back to find xx

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