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12 questions from this quiz
The xxx-axis
The yyy-axis
vx=vcosθv_x = v \cos \thetavx=vcosθ
vy=vsinθv_y = v \sin \thetavy=vsinθ
Cosine and sine
It remains constant
Gravity
9.81 m/s² downward
x=vx⋅tx = v_x \cdot tx=vx⋅t
Yes, linked only by time of flight
17.32 m/s
10 m/s
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