Product Rule (Edexcel A-Level Mathematics): Quizzes

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Product Rule
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What is the product rule formula for differentiating u(x)⋅v(x)u(x) \cdot v(x)?

u(x)⋅v′(x)+v(x)⋅u′(x)u(x) \cdot v'(x) + v(x) \cdot u'(x)

What does the product rule account for when differentiating?

Both ways the product can change

Find dydx\frac{dy}{dx} for y=x2sin⁡(x)y = x^2 \sin(x).

x2cos⁡(x)+2xsin⁡(x)x^2 \cos(x) + 2x \sin(x)

Find dydx\frac{dy}{dx} for y=exln⁡(x)y = e^x \ln(x).

exx+exln⁡(x)\frac{e^x}{x} + e^x \ln(x)

Which step comes LAST when applying the product rule?

Add the two results together

Find dydx\frac{dy}{dx} for y=x2e3xy = x^2 e^{3x} (factorised form).

e3x(3x2+2x)e^{3x}(3x^2 + 2x)

Find dydx\frac{dy}{dx} for y=(3x2+2x)cos⁡(x)y = (3x^2 + 2x) \cos(x).

−(3x2+2x)sin⁡(x)+(6x+2)cos⁡(x)-(3x^2 + 2x)\sin(x) + (6x + 2)\cos(x)

Find dydx\frac{dy}{dx} for y=xsin⁡xy = x \sin x.

sin⁡x+xcos⁡x\sin x + x \cos x

The alternative notation (uv)′=vu′+uv′(uv)' = vu' + uv' is equivalent to which formula?

u(x)⋅v′(x)+v(x)⋅u′(x)u(x) \cdot v'(x) + v(x) \cdot u'(x)

Find dydx\frac{dy}{dx} for y=3x4e2x+3y = 3x^4 e^{2x+3} (factorised form).

6x3e2x+3(2+x)6x^3e^{2x+3}(2+x)

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